bralex wrote: ↑Wed Jan 25, 2023 7:29 am
Rik, is there a book you can point me too that discusses this type of calculation and the theory behind it? I'd like to understand better.
I suggest to start with the
"FAQ: How can I calculate effective aperture?".
Then if you have more questions, ask. I have not found any book that concisely explains what matters for our work. The material is
in the books, of course, but it is scattered over many pages and expressed in ways that are often difficult to interpret and apply.
If I plug the numbers for the Mitty 20x (NA = 0.42) I get f=23.8; does that suggest that I will not get sharp results using one?
I agree with your calculation of effective f/23.8 at rated magnification, and yes, that will be strongly in diffraction territory on most modern sensors.
Or, you can put the same objective on a 100 mm tube lens so that it operates at 10X. In that case the effective aperture will be 10/(2*0.42) = f/11.9, and if you're using APS-C, the whole sensor will be covered by high quality image.
In both configurations the object-side NA is 0.42, so both configurations give the same potential resolution on subject.
The 10X configuration will be sharper
on sensor because it packs the same information into half the distance. However, the 10X image will not be sampled as well because of sensor issues like pixel size, Bayer filter, and anti-aliasing. So in practice,
on subject the 10X configuration may not show as much detail as the 20X configuration.
This tradeoff between "sharp" and "detailed" is a constant issue in digital photography. There is a long discussion in the old thread at
viewtopic.php?t=2439 .
--Rik